Stanford Encyclopedia of Philosophy

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Proof of Proposition 2.18

Proposition 2.18.
Let C*N be the greatest fixed point of fE. Then C*N(E) = K*N(E).


We have shown that K*N(E) is a fixed point of fE, so we only need to show that K*N(E) is the greatest fixed point. Let B be a fixed point of fB. We want to show that BKkN(E) for each value k≥1. We will proceed by induction on k. By hypothesis,

B = fE(B) = K1N(EB) ⊆ K1N(E)
by monotonicity, so we have the k=1 case. Now suppose that for k=m, BKmN(E). Then by monotonicity,
(i) K1N(B) ⊆ K1NKmN(E) = Km+1N(E)
We also have:
(ii) B = K1N(EB) ⊆ K1N(B)
by monotonicity, so combining (i) and (ii) we have:
BK1N(B) ⊆ Km+1N(E)
completing the induction. QED

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