# How do you solve #8^(2x-4)=16^(2x+4)#?

##### 2 Answers

I got:

#### Explanation:

Let us take the log in base

we now use the definition of log to solve the two logs and get:

rearrange and solve for

#### Explanation:

Some exponential equations need to be solved using logs, others can be solved by making the bases or the indices the same.

This is an example of the latter.

Both 8 and 16 are powers of 2, so we can write this equation in terms of a common base on each side.